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Draw the graph of y=x^(2)+5x+6 and find its zeroes-5x2y=6 Get it in y=mxb form 2y=5x 6 (subtract 5x from both sides) y= (5/2)x 3 (divide both sides by 2) Graph the equation 3 is the yintercept, so plot a point at (0,3) 5/2 is the slope The top number is the change in y, bottom number is change in x Since you already have a point at (0,3), go up 5 and right 2 and put a point atSin (x)cos (y)=05 2x−3y=1 cos (x^2)=y (x−3) (x3)=y^2 y=x^2 If you don't include an equals sign, it will assume you mean " =0 " It has not been well tested, so have fun with it, but don't trust it If it gives you problems, let me know Note it may take a few seconds to finish, because it has to do lots of calculations
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The graph y = f (x) = y=x^ (2)5x6 (y equally x to the power of (2) minus 5x plus 6) plot the function graph and draw it Curve sketching this function THERE'S THE ANSWER! online Plotting a function graph / y=x^ (2)5x6 Graphing y = y=x^ (2)5x6 The solution You have entered src 2 f (x) = x 5*x 6 f ( x) = ( x 2 − 5 x) 6Wataru This quadratic function has no real roots, but if you are looking for its complex roots, then by Quadratic Formula, we have x = 2⋅ 1−3± 32 −4⋅ 1⋅ 6 = 2−3± −15 = 2−3± 15 i
Incoming Term: y=x^2-5x+6 graph, draw the graph of y=x^(2)+5x+6 and find its zeroes, sketch the graph of y=x^2-5x+6,
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